💯 Daily LeetCode Challenge Day_14 - Angle between hands of a clock

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문제

Given two numbers, hour and minutes. Return the smaller angle (in degrees) formed between the hour and the minute hand.

Example 1:

Input: hour = 12, minutes = 30 Output: 165

Example 2:

Input: hour = 3, minutes = 30 Output: 75

Example 3:

Input: hour = 3, minutes = 15 Output: 7.5

Example 4:
Input: hour = 4, minutes = 50 Output: 155

Example 5:
Input: hour = 12, minutes = 0 Output: 0

Constraints:

• 1 <= hour <= 12
• 0 <= minutes <= 59
• Answers within 10^-5 of the actual value will be accepted as correct.

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분침에 따라 시침도 바뀐다는 것과 360도는 0도로 바꿔주는 것, 두 침의 작은 각을 반환해야 하는것만 생각해주면 된다.

class Solution {
    func angleClock(_ hour: Int, _ minutes: Int) -> Double {
        var mAngle : Double = 6*Double(minutes)
        var hAngle : Double = ( (30*Double(hour)) + (30*Double(minutes)/60) )
        if hAngle >= 360 { hAngle -= 360 }
        var minAngle = min(abs(hAngle-mAngle),abs(mAngle-hAngle))
        return min(abs(360-minAngle),minAngle)
    }
}